We have a principal which compound its interest quarterly.
The annual nominal rate is 3.56%.
The principal is $1350.
We can express the amount in the account with the expression:
[tex]FV=PV\cdot(1+\frac{r}{m})^{n\cdot m}[/tex]where FV: future value, PV: present value, r: annual interest rate, n: number of years, m: number of subperiods a year.
In this problem, r=0.0356, PV=1350 and m=12/3=4
In this case, for a period of 6 months, we have n=0.5, so the calculation gives a final vlaue of:
[tex]FV=1350\cdot(1+\frac{0.0356}{4})^{0.5\cdot4}=1350\cdot1.0089^2\approx1350\cdot1.018\approx1374.14[/tex]Substracting the principal of 1350, the interest is:
[tex]I=1374.14-1350=24.14[/tex]For a one-year period, n=1, so we can calculate the final value as:
[tex]FV=1350\cdot(1+\frac{0.0356}{4})^{1\cdot4}=1350\cdot1.0089^4\approx1350\cdot1.0361\approx1398.71[/tex]Again, by substracting the principal, we can get the compounded interest:
[tex]I=1398.71-1350=48.71[/tex]A. For a period of 6 months, the interest is $24.14.
B. The balance at 6 months from the deposit is $1374.14.
C. For a period of one-year, the interest is $48.71.
D. The balance at one year from the deposit is $1398.71.