need help. Two options is right I just don't know

The correct options are A, B and C
Here, we want to select which of the given expressions have the same value as 1/4
Three important laws of indices are needed to get this;
[tex]\begin{gathered} \frac{a^x}{a^y}=a^{x-y} \\ \\ a^x\text{ }\times a^y=a^{x+y} \\ \\ a^{-1\text{ }}\text{ = }\frac{1}{a} \end{gathered}[/tex]So, with these laws, we can actually proceed to solve the question. Let us consider the options one after the other
a) we have;
[tex]\frac{2^4}{2^6\text{ }}=2^{4-6}=2^{-2\text{ }}=\text{ }\frac{1}{2^2}\text{ = }\frac{1}{4}[/tex]b) we have;
[tex]\frac{(4^3)(4^2)}{(4^2)^3}\text{ = }\frac{4^{3+2}}{4^6}\text{ = }\frac{4^5}{4^6}=4^{5-6}=4^{-1}\text{ = }\frac{1}{4}[/tex]c) We have;
[tex](2^5)(2^{-7})=2^{5-7}=2^{-2}\text{ = }\frac{1}{2^2}\text{ = }\frac{1}{4}[/tex]d) We have;
[tex](4^5)(4^{-3})=4^{5-3}=4^2\text{ = 16}[/tex]As we can see, options A, B and C are correct