Respuesta :

we must find the are of the triangle and the area of the half circle and sum them

Triangle

[tex]A_1=\frac{b\times h}{2}[/tex]

where b is the base and is 16 because is the diameter of the circle and h is the height 15

so replacing

[tex]\begin{gathered} A_1=\frac{16\times15}{2} \\ \\ A_1=120 \end{gathered}[/tex]

the area is 120 cm2

Half circle(area of the circle between 2)

[tex]A_2=\frac{\pi\times r^2}{2}[/tex]

where r is the radius 8

[tex]\begin{gathered} A_2=\frac{\pi\times8^2}{2} \\ \\ A_2=32\pi\approx100.5 \end{gathered}[/tex]

the area is 100.5 cm2

Total area

[tex]A_T=A_1_{}+A_2^{}[/tex][tex]\begin{gathered} A_T=120+100.5 \\ A_T=220.5 \end{gathered}[/tex]

the total area is 220.5cm2

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