Question

If using the method of completing the square to solve the quadratic equation, which number would have to be added to “complete the square”?

X^2+7x-4=0

Answer 1

Problem

$x^2\text{ + 7x - 4 = 0}$

Step 1:

a = 1 b = 7 and c = -4

Step 2:

The number that you will add to complete the square is square of half of the coefficient of x.

$\begin{gathered} \text{The number that must be added to complete the square} \\ =\text{ }(\frac{7}{2})^2 \\ =\text{ }\frac{49}{4} \end{gathered}$

The number that you will add to complete the square = 49/4

To solve the equation complete, first move the constant value to the right hand side.

$x^2\text{ + 7x = 4}$

Next, add 49/4 to both sides.

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