Question

How much charge is transferred by a 0.80 A current in 19 minutes?

Answer 1

Given that the current is I = 0.80 A

and the time taken is

$\begin{gathered} t\text{ = 19 minutes} \\ =19\times60\text{ seconds} \\ =1140\text{ s} \end{gathered}$

We have to find the charge, q.

The formula to calculate the charge is

$q=I\times t$

Substituting the values, the charge will be

$\begin{gathered} q\text{ = }0.80\times1140 \\ =912\text{ C} \end{gathered}$

Thus, the charge is 912 C.