Question

You know 45% of UWS students like pepperoni pizza, 72% of students like cheese pizza, and 31% of UWS students like BOTH pepperoni and cheese pizza. If you select a student from school at random, what is the probability they link pepperoni pizza OR cheese pizza?I don’t know this question!Can you give me answer with solution processing?

Answer 1

Answer:

0.86

Explanation:

Given:

• The percentage who like pepperoni pizza, Pr(P)=45%=0.45

,

• The percentage who like cheese pizza, Pr(C)=72%=0.72

,

• The percentage who like both, Pr(P∩C)=31%=0.31

We want to find the probability that a randomly selected student likes pepperoni pizza OR cheese pizza, Pr(P∪C).

From probability theory:

$\begin{gathered} Pr(P\cup C)=Pr(P)+Pr(C)-Pr(P\cap C) \\ =0.45+0.72-0.31 \\ =0.86 \end{gathered}$

The probability that a randomly selected student likes pepperoni pizza OR cheese pizza is 0.86.