Question

Part II Dilution Problems: 20. A bottle is labeled 12,0 M HCI. What volume of the original HCl is required to make 20.0 mL of 3.0 M HCl solution?

Answer 1

Answer:

$5.0\text{ mL}$

Explanation:

Here, we want to get the volume needed to make 20 mL of 3 M HCl

Mathematically, according to the dilution formula:

$C_1V_1\text{ = C}_2V_2$

Where C1, V1 are the initial molarity and volume respectively, while:

C2, V2 are the final molarity and volume respectively

Substituting the values, we have it that:

$\begin{gathered} 12\text{ }\times\text{ V}_1\text{ = 20 }\times\text{ 3} \\ V_1\text{ = }\frac{20\times3}{12} \\ V_1\text{ = 5 mL} \end{gathered}$