Solution:
Consider the following quadratic equation:
[tex](x+7)^2-49=0[/tex]solving for the square, this is equivalent to:
[tex](x+7)^2=49[/tex]Taking the square root of both sides of the equation, we obtain:
[tex]x+7=\pm\sqrt[]{49}[/tex]this is equivalent to:
[tex]x+7=\pm7[/tex]so, solving for x, we get two solutions:
Solution 1:
[tex]x=-7+7=0[/tex]Solution 2:
[tex]x=-7-7\text{ = -14}[/tex]So that the correct answer is:
[tex]x=0[/tex][tex]x=\text{-14}[/tex]