Respuesta :

Solution:

Consider the following quadratic equation:

[tex](x+7)^2-49=0[/tex]

solving for the square, this is equivalent to:

[tex](x+7)^2=49[/tex]

Taking the square root of both sides of the equation, we obtain:

[tex]x+7=\pm\sqrt[]{49}[/tex]

this is equivalent to:

[tex]x+7=\pm7[/tex]

so, solving for x, we get two solutions:

Solution 1:

[tex]x=-7+7=0[/tex]

Solution 2:

[tex]x=-7-7\text{ = -14}[/tex]

So that the correct answer is:

[tex]x=0[/tex]

[tex]x=\text{-14}[/tex]

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