Step 1
Given;
[tex]\begin{gathered} Principal=8201 \\ r=2.47=\frac{2.47}{100}=0.0247 \end{gathered}[/tex]Step 2
State the formula for if interest is compound
[tex]A=P(1+\frac{r}{n})^{nt}[/tex][tex]\begin{gathered} A=8201\times2=\text{ \$}16402 \\ 16402=8201(1+\frac{0.0247}{1})^{1\times t} \\ \frac{16402}{8201}=\frac{8201(1+\frac{0.0247}{1})^{1\times t}}{8201} \\ 2=(1+\frac{0.0247}{1})^t \end{gathered}[/tex][tex]\begin{gathered} 2=(1.0247)^t \\ ln2=tln(1.0247) \\ t=\frac{ln2}{ln(1.0247)}=28.4078031 \\ t\approx28\text{ years} \end{gathered}[/tex]Answer; Using interest compounded yearly the time taken for the amount to double is;
[tex]28\text{ years to the nearest whole number}[/tex]