Solution:
Given the equation below;
[tex]x^2-6x+36[/tex]
For a perfect square polynomial,
[tex]\begin{gathered} ax^2+bx+c=0 \\ (\frac{b}{2})^2 \end{gathered}[/tex]
Where
[tex]b=-6[/tex][tex](\frac{b}{2})^2=(-\frac{6}{2})^2=(-3)^2=9[/tex]
Where for a perfect trinomial,
[tex]x^2+2ax+a^2[/tex]
And
[tex]\begin{gathered} a^2=(-3)^2=9 \\ a^2=(\frac{b}{2})^2 \\ S\imaginaryI nce,\text{ a}^236 \end{gathered}[/tex]
Hence, it is not a perfect square trinomial.
