Answer:
y=-(2/5)x+2
Explanation:
Given the equation of the line:
[tex]2x+5y-10=0[/tex]The slope-intercept form of a line is given as y=mx+b.
Thus, make y the subject of the given equation.
[tex]\begin{gathered} 5y=-2x+10 \\ \text{Divide all through by 5} \\ y=-\frac{2}{5}x+\frac{10}{5} \\ y=-\frac{2}{5}x+2 \end{gathered}[/tex]The slope-intercept form of the equation is y=-(2/5)x+2.
Next, the lines are graphed using the intercepts.
When y=0
[tex]\begin{gathered} 0=-\frac{2}{5}x+2\implies\frac{2}{5}x=2 \\ \text{Multiply both sides by }\frac{5}{2} \\ \frac{2}{5}\times\frac{5}{2}x=2\times\frac{5}{2} \\ x=5 \end{gathered}[/tex]• The x-intercept is (5,0)
,• From the slope-intercept form, the y-intercept is (0,2).
Join the two points using a straight line as shown below:
