Answer:
The magnitude of the vectior = 44.38 units
Direction of the vector, θ = -14.47
Explanations:
The vector points -43.0 units along the X-axis, and 11.1 units along the y-axis.
This can be graphically illustrated as shown below:
x = -43
y = 11.1
The magnitude, R, is calculated using the Pythagora's theorem
[tex]\begin{gathered} R^2=x^2+y^2 \\ R^2=(-43)^2+(11)^2 \\ R^2\text{ = }1849+121 \\ R^2\text{ = }1970 \\ R\text{ = }\sqrt[]{1970} \\ R\text{ = }44.38 \end{gathered}[/tex]
The magnitude of the vectior = 44.38 units
The direction of the vector is calculated below:
[tex]\begin{gathered} \tan ^{}\theta\text{ = }\frac{\text{Opposite}}{\text{Adjacent}} \\ \tan \theta\text{ = }\frac{11.1}{-43} \\ \tan \theta\text{ = -}0.258 \\ \theta\text{ = }\tan ^{-1}(-0.258) \\ \theta\text{ = }-14.47^0 \end{gathered}[/tex]
