Solution:
Given:
[tex]1-3x>14-(4-6x)[/tex]
Solving the given inequality with the steps involved,
[tex]\begin{gathered} 1-3x>14-(4-6x) \\ E\text{ xpanding the bracket on the r}ight\text{ hand side of the inequality;} \\ 1-3x>14-4+6x \\ 1-3x>10+6x \\ \text{Collecting the like terms;} \\ 1-10>6x+3x \\ -9>9x \\ \text{Dividing both sides by 9,} \\ -\frac{9}{9}>\frac{9x}{9} \\ -1>x \\ \text{Flipping the sides, and changing the inequality using the principle if a>b, then bx, } \\ \text{then} \\ x<-1 \end{gathered}[/tex]
Therefore, the solution as inequality is;
[tex]x<-1[/tex]
The solution in interval notation therefore is;
[tex](-\infty,-1)[/tex]
Graphing the solution on a number line;
