Question

Evaluate the expression when x=4 and y=8.yery+3.rSimplify your answer as much as possible.

Answer 1

$\begin{gathered} x=4 \\ y=8 \end{gathered}$$\frac{y^2-x}{y+3x}$$\frac{y^2-x}{y+3x}=\frac{8^2-4}{8+3(4)}=\frac{64-4}{20}=\frac{60}{20}=3$