hello
the quadratic equation given is
[tex]x^2-4x+3=0[/tex]
now let's find two factors to the equation and proceed to solve the equation.
to do this, i'll write down the standard form of a quadratic equation out
[tex]ax^2+bx+c=0[/tex]
to solve this by factorization, we need to find two numbers that when they're multiplied will give us the value of c but when added will give the value of b
in this case, our value of b = -4 and c = 3
two numbers that will give us the desired value are (-1, -3)
[tex]x^2-4x+3=(x-1)(x-3)[/tex]
the factorized form of the equation would be (x - 1)(x - 3)
