Question

The vertices of ABC are A(2, - 2), B(-2, - 2), and C(4,4). For the translation below, give the vertices of AA'B'C'. T(24)(ABC) The vertices of AA'B'C' are A and c'o (Simplify your answers. Type ordered pairs.)

Answer 1

The given vertices are A(2, -2), B(-2, -2), and C(4,4).

The given transformation is

$T_{(2,4)}(\Delta ABC)$

This transformation means an addition of 2 units to x-coordinates and an addition of 4 to y-coordinates. So, the new transformations are

A'(2+2, -2+4) = A'(4, 2).

B'(-2+2, -2+4) = B'(0, 2)

C'(4+2, 4+4) = C'(6, 8).

Therefore, the vertices are A'(4, 2), B'(0, 2), and C'(6, 8).