Given f(x)= -12x^2+27 and g(x) ≠0, find (f/g)(x) PLEASE HELP

Answer:
[tex]\frac{f(x)}{g(x)}=-2x+3[/tex]Step-by-step explanation:
Given the following functions, divide f(x) by g(x):
[tex]\begin{gathered} f(x)=-12x^2+27 \\ g(x)=6x-9 \\ Then, \\ \frac{f(x)}{g(x)}=_{}\frac{-12x^2+27}{6x-9} \end{gathered}[/tex]Hence,
[tex]\begin{gathered} \frac{f(x)}{g(x)}=_{}\frac{-12x^2+27}{6x-9} \\ \frac{f(x)}{g(x)}=-2x+3 \end{gathered}[/tex]