Question

A research study asked 1749 homeowners how many bedrooms were in their homes. The results are shown in the table below. What is the probability that a homeowner chosen at random has 3 bedrooms? # of bedrooms # of homeowners12 or less. 4903. 5774. 4555 ot more. 227Answers:13%26%28%33%

Answer 1

Probability that a homeowner chosen at random has 3 bedrooms:

$\begin{gathered} P(3\text{ bedrooms)=}\frac{\#homeowners\text{ with 3 bedrooms}}{\#\text{total homeowners}} \\ \\ P(3\text{ bedrooms)=}\frac{577}{490+577+455+227}=\frac{577}{1749}\approx0.33 \end{gathered}$

Multiply the probability by 100 to get it in %:

$0.33\cdot100=33$

Then, the probability that a homeowner chosen at random has 3 bedrooms is 33%