In our table, we have the following set of values for the frequency:
[tex]\lbrace9,6,4,7,4\rbrace[/tex]
The mean of a dataset is the sum of all elements divided by the total amount of elements. The mean of our set is:
[tex]\bar{x}=\frac{\sum_{i\mathop{=}1}^5x_i}{5}=\frac{9+6+4+7+4}{5}=\frac{30}{5}=6[/tex]
The mean of the frequency is equal to 6.
The mode is the number that appears the most in given data which is 4 since it is given two times.
To find the median we need to reorder our dataset in ascending order.
[tex]\lbrace4,4,6,7,9\rbrace[/tex]
The median is the middle number in a sorted, ascending or descending, list of numbers. In our problem, the middle element is 6, therefore, the median is 6.
The maximum value of our dataset is 9 and the minimum value is 4, therefore, the midrange is:
[tex]\frac{9+4}{2}=\frac{13}{2}=6.5[/tex]
The midrange of the dataset is 6.5.