Respuesta :

In ths problem, we need to graph a linear equation in standard form: ax + by = c

The easiest way to do this is to use the x-intercept and y-intercept:

- x-intercept, where the graph crosses the x-axis when y = 0

- y-intercept, where the graph crosses the y-axis when x = 0

We are given the equation

[tex]-12x+6y=-12[/tex]

To find the x-intercept, we will let y = 0, then solve for x. So,

[tex]\begin{gathered} -12x+6(0)=-12 \\ -12x=-12 \end{gathered}[/tex]

Divide by -12 on both sides:

[tex]\begin{gathered} \frac{-12}{-12}x=\frac{-12}{-12} \\ \\ x=1 \end{gathered}[/tex]

The x-intercept is at x = 1, so the point we can graph is (1,0):

Next, we can find the y-intercept by letting x = 0. That gives us:

[tex]\begin{gathered} -12(0)+6y=-12 \\ \\ 6y=-12 \end{gathered}[/tex]

Divide both sides by 6:

[tex]\begin{gathered} \frac{6y}{6}=-\frac{12}{6} \\ \\ y=-2 \end{gathered}[/tex]

So the y-intercept is y = -2 at the point (0,-2). We can graph that point next:

Finally, we can u

Ver imagen KenniyaN344580
Ver imagen KenniyaN344580
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