Respuesta :
In ths problem, we need to graph a linear equation in standard form: ax + by = c
The easiest way to do this is to use the x-intercept and y-intercept:
- x-intercept, where the graph crosses the x-axis when y = 0
- y-intercept, where the graph crosses the y-axis when x = 0
We are given the equation
[tex]-12x+6y=-12[/tex]To find the x-intercept, we will let y = 0, then solve for x. So,
[tex]\begin{gathered} -12x+6(0)=-12 \\ -12x=-12 \end{gathered}[/tex]Divide by -12 on both sides:
[tex]\begin{gathered} \frac{-12}{-12}x=\frac{-12}{-12} \\ \\ x=1 \end{gathered}[/tex]The x-intercept is at x = 1, so the point we can graph is (1,0):
Next, we can find the y-intercept by letting x = 0. That gives us:
[tex]\begin{gathered} -12(0)+6y=-12 \\ \\ 6y=-12 \end{gathered}[/tex]Divide both sides by 6:
[tex]\begin{gathered} \frac{6y}{6}=-\frac{12}{6} \\ \\ y=-2 \end{gathered}[/tex]So the y-intercept is y = -2 at the point (0,-2). We can graph that point next:
Finally, we can u


