Question

The coordinates of quadrilateral FGHJ are F(-5, -3), G(-3, 3), H(3, 5), and J(7, -1). Find the midpoint of FGa- 0,4b- 1,-2c- 5,2d- -4,0

Answer 1

In this case, since we have to find the midpoint of FG, we only need to focus on that segment. In order to find the midpoint of a line that focuses through the points (x1,y1) and (x2,y2), we can apply the formula:

$\begin{gathered} xm=\frac{x1+x2}{2} \\ ym=\frac{y1+y2}{2} \end{gathered}$

Where xm is the x-coordinate and ym the y-coordinate of the midpoint (xm,my), in this case the points of the segment FG are (-5,-3) and (-3,3), if we replace s their values into the above equation, we get:

$\begin{gathered} xm=\frac{-5+(-3)}{2}=\frac{-5-3}{2}=\frac{-8}{2}=-4 \\ ym=\frac{-3+3}{2}=\frac{0}{2}=0 \end{gathered}$

Then, the midpoint of FG is (-4,0)