Given,
The weight of the cat, W=1200 N
The angle of inclination, θ=36°
The component of the weight that holds the cat against the inclined plane is the vertical component.
The vertical component of the cat's weight is given by,
[tex]W_y=W\cos \theta[/tex]
On substituting the known values,
[tex]\begin{gathered} W_y=1200\times\cos 36^{\circ} \\ =970.8\text{ N} \\ \approx970\text{ N} \end{gathered}[/tex]
Thus the value of the component of the cat's weight that holds it against the inclined plane is 970 N
Therefore the correct answer is option 2.
