Question

3. If I contain 3.99 moles of gas in a container with a volume of 65.9 liters and aa temperature of 410 K, what is the pressure inside the container (in atm)?

Answer 1

Answer

The pressure, P inside the container (in atm) = 2.04 atm

Explanation

Given:

Moles of the gas, n = 3.99 mol

Volume, V = 65.9 L

Temperature, T = 410 K

What to find:

The pressure, P inside the container (in atm).

Step-by-step solution:

The pressure, P inside the container (in atm) can be calculated using the ideal gas equation.

$PV=nRT$

R is the molar gas constant and R = 0.0821 atm-liter / mol.K

Putting the values of the parameters into the formula, we have

$\begin{gathered} P\times65.9L=3.99mol\times0.0821atm.L\text{/}mol.K\times410K \\ \\ P=\frac{3.99mol\times0.0821atm.L\text{/}mol.K\times410K}{65.9L} \\ \\ P=2.04\text{ }atm \end{gathered}$

The pressure, P inside the container (in atm) = 2.04 atm