Answer:
[tex]T=4\times10^2s[/tex]Explanation: The time needed for the 2.00C charge to pass at a current of 5.00mA is:
[tex]I=5.00mA=5.00\times10^{-3}\rightarrow I=5.00\times10^{-3}\frac{C}{s}[/tex]Therefore time is:
[tex]\begin{gathered} T=\frac{Q}{I}=\frac{2C}{(5.00\times10^{-3}\frac{C}{s})}=\frac{2}{5}\times10^3s \\ \therefore\Rightarrow \\ T=0.4\times10^3s=4\times10^2s \\ T=4\times10^2s \end{gathered}[/tex]Note! Q is for charge and I is for current