ANSWER
10.80 m/s
EXPLANATION
Given:
• The student's displacement, Δx = 27.00 m
,• The time it took the student to run that distance, Δt = 2.50 s
Find:
• The student's average velocity, v
The average velocity is given by,
[tex]\bar{v}=\frac{\Delta x}{\Delta t}[/tex]Substitute the known values and solve,
[tex]\bar{v}=\frac{27.00m}{2.50m}=10.80m/s[/tex]Hence, the average velocity of the student is 10.80 m/s.