Question

1.What are the zeros of the polynomial function?
f(x)=x^2+9x+20
2.What are the zeros of the polynomial function?
f(x)=x^2−4x−60

3.What are the roots of the equation?
x^2+24=14x

4.What are the zeros of the function?
g(x)=x^2−x−72

Answer 1

1. X^2+9x+20
=x^2+(4+5)x+20
=x^2+4x+5x+20
=x(x+4)+5(x+4)
=(x+4)(x+5)
So zeroes are -4 and -5

2.x^2-4x-60
=x^2-(10-6)x-60
=x^2-10x+6x-60
=x(x-10)+6(x-10)
=(x-10)(x+6)
So zeroes are 10 and -6

3.x^2+24=14x
=x^2-14x+24
=x^2-(12+2)x+24
=x^2-12x-2x+24
=x(x-12)-2(x-12)
=(x-12)(x-2)
So zeroes are 12 and 2

4.x^2-x-72
=x^2-(9-8)x-72
=x^2-9x+8x-72
=x(x-9)+8(x-9)
=(x-9)(x+8)
So the zeroes are 9 and -8