The roots of the polynomial function are x=-2, x=5 and x=-6
You can express them as
(x+2)(x-5)(x+6)=0
To reach the cubic function you have to expand this expression.
Apply the distributive propperty of multiplications to solve.
First multiply the first two parentheses:
[tex]\begin{gathered} (x+2)(x-5)=x^2-5x+2x-10 \\ x^2-3x-10 \end{gathered}[/tex]Next multiply this result to the third parentheses:
[tex]\begin{gathered} (x^2-3x-10)(x+6)=x^3+6x^2-3x^2-18x-10x-60\text{ \rightarrow{}Symplify} \\ x^3+3x^2-28x-60 \end{gathered}[/tex]The solution is the third option.
[tex]f(x)=x^3+3x^2-28x-60[/tex]