For this type of question, we use the properties of fractions addition.
1.-
[tex]\begin{gathered} -\frac{2}{3}+(-\frac{1}{6})=-\frac{2}{3}-\frac{1}{6}=-\frac{2}{3}\cdot\frac{2}{2}-\frac{1}{6} \\ =-\frac{4}{6}-\frac{1}{6}=-\frac{5}{6} \\ -\frac{2}{3}+(-\frac{1}{6})=-\frac{5}{6} \end{gathered}[/tex]2.-
[tex]\begin{gathered} -\frac{1}{4}+(-\frac{3}{8})=-\frac{1}{4}-\frac{3}{8}=-\frac{1}{4}\cdot\frac{2}{2}-\frac{3}{8} \\ =-\frac{2}{8}-\frac{3}{8}=-\frac{5}{8} \\ -\frac{1}{4}+(-\frac{3}{8})=-\frac{5}{8} \end{gathered}[/tex]3.-
[tex]\begin{gathered} -\frac{1}{4}+(-\frac{1}{2})=-\frac{1}{4}-\frac{1}{2}=-\frac{1}{4}-\frac{1}{2}\cdot\frac{2}{2} \\ =-\frac{1}{4}-\frac{2}{4}=-\frac{3}{4} \\ -\frac{1}{4}+(-\frac{1}{2})=-\frac{3}{4} \end{gathered}[/tex]