Respuesta :

We have the parabolic equation:

[tex](x-2)^2=12(y-3)[/tex]

This equation is expressed in vertex form.

The vertex is (2,3).

As the square term is applied to the term with x, the axis of symmetry is vertical (x = 2).

We are left then with two options.

As the quadratic coefficient is positive (a = 1/12, if we rearrange the equation), the parabola opens upward.

Then, the corresponding graph is Option B:

Answer: Option B

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