Question 410What is the length of line segment DK to the nearest tenth of an inch?

The Solution:
Given the figure below:
We are required to find the length of DK to the nearest tenth of an inch.
By the Trigonometrical Ratio, we have that:
[tex]\sin 43^o=\frac{\text{opp}}{\text{hyp}}=\frac{16}{DK}[/tex][tex]\sin 43^o=\frac{16}{DK}[/tex]Cross multiplying, we get
[tex]DK\sin 43^o=16[/tex]Dividing both sides by sin43, we get
[tex]DK=\frac{16}{\sin 43^o}=23.4605\approx23.5^o[/tex]Therefore, the correct answer is 23.5 degrees.