Given the equation:
[tex]8\times(4\times y)-5x=y[/tex]Multiply:
[tex]\begin{gathered} 8\times4y-5x=y \\ 32y-5x=y \end{gathered}[/tex]Then solve for x:
[tex]\begin{gathered} 32y-5x-32y=y-32y \\ -5x=-31y \\ \frac{-5x}{-5}=\frac{-31y}{-5} \\ x=\frac{31y}{5} \end{gathered}[/tex]Answer:
[tex]x=\frac{31y}{5}[/tex]