Question

If it takes 221J of work to do this what is the combined mass of the dog and the basket

Answer 1

We are given that 221J of work is required to lift a mass of 4.75 meters. The amount of work is determined by the following equation:

$W=Fd$

Where:

$\begin{gathered} F=\text{ force} \\ d=\text{ distance} \end{gathered}$

The force is equivalent to the combined weight if the dog and the basket multiplied by the acceleration of gravity:

$F=mg$

The distance is the height that the basket is lifted:

$d=h$

Now, we substitute in the equation:

$W=mgh$

Now, we divide by "gh":

$\frac{W}{gh}=m$

Now, we substitute the values:

$\frac{221J}{(9.8\frac{m}{s^2})(4.75m)}=m$

Solving the operations:

$4.75kg=m$

Therefore, the combined mass is 4.75 kg.