Question

(0,2) and(8,0) Write an equation in standard form of the line that passes through the given points

Answer 1

To find the equation of a line that pasess through two ponit, we'll first have to calculate the slope, using the formula:

$m=\frac{y_2-y^{}_1}{x_2-x_1}$

Therefore,

$m=\frac{0-2}{8-0}\rightarrow m=\frac{-2}{8}\rightarrow m=-\frac{1}{4}$

Then, we use the point-slope form equa with the slope we just found and the point (8,0)

$\begin{gathered} y-0=-\frac{1}{4}(x-8)\rightarrow y=-\frac{1}{4}x+2\rightarrow y-2=-\frac{1}{4}x \\ \rightarrow-4y+8=x\rightarrow8=x+4y \\ \text{Therefore, the equation of the line is:} \\ x+4y=8 \end{gathered}$