m^2-6m-16=0
We have a quadratic expression:
am^2+bm+c =0
Where:
a= 1
b= -6
c= -16
Apply the quadratic formula:
(-b±√(b²-4ac))/(2a)
(-(-6)±√((-6)²-4(1)-16))/(2x1)
(6±√(36+64))/(2)
(6± √100 )/2
(6± 10 )/2
Positive: (6+10)/2 =16 /2 = 8
Negative : (6-10)/2 = -4/2 =-2
m1= 8
m2=-2
