Question

A motorcycle traveling along a straight road increases its speed from 30 ft/s to 53.9 ft/sin a distance of 184 feet. If the acceleration is constant, how many seconds of timeelapses while the motorcycle moves this distance?

Answer 1

First, let's calculate the acceleration, using Torricelli's equation:

$\begin{gathered} V^2=V_0^2+2\cdot a\cdot d\\ \\ 53.9^2=30^2+2\cdot a\cdot184\\ \\ 2905.21=900+368a\\ \\ 368a=2005.21\\ \\ a=5.45\text{ m/s^^b2} \end{gathered}$

Now, to find the time, we can use the following formula:

$\begin{gathered} V=V_0+a\cdot t\\ \\ 53.9=30+5.45t\\ \\ 5.45t=23.9\\ \\ t=4.385\text{ s} \end{gathered}$