Given the following question:
[tex](x-1)(3x+8)=0[/tex][tex]\begin{gathered} \mleft(x-1\mright)\mleft(3x+8\mright)=0 \\ (x-1)=0 \\ -1+1=0 \\ 0+1=1 \\ x=1 \\ \\ (3x+8)=0_{} \\ 8-8=0 \\ 0-8=-8 \\ 3x=-8 \\ 3x\div3=x \\ -8\div3=-\frac{8}{3} \\ x=-\frac{8}{3} \end{gathered}[/tex]
Your answers are x = 1, and x = -8/3.
