Given:
The objective is to find the value of x.
Since the given triangle is a right angled triangle, the value of x can be solved using Pythagoras theorem.
[tex]\begin{gathered} \text{Hypotenuse}^2=Opposite^2+Adjacent^2 \\ 10^2=x^2+4^2 \\ x^2=10^2-4^2 \\ x^2=100-16 \\ x^2=84 \\ x=\sqrt[]{84} \\ x=\sqrt[]{2\cdot2\cdot3\cdot7} \\ x=2\sqrt[]{21} \end{gathered}[/tex]
Hence, the value of x is 2√21.
