Solve the following system, using substitution
[tex]\begin{bmatrix}B=5c+9 \\ B=-4c-9\end{bmatrix}[/tex]Substitute B = -4c-9
[tex]-4c-9=5c+9[/tex]clear C
[tex]\begin{gathered} -4c-9+9=5c+9+9 \\ -4c=5c+18 \\ -4c-5c=5c+18-5c \\ -9c=18 \\ \frac{-9c}{-9}=\frac{18}{-9} \\ c=-2 \end{gathered}[/tex]We have found that C = -2
Now, let's find B
Substitute C = -2;
[tex]B=-4\mleft(-2\mright)-9[/tex][tex]B=-1[/tex]Thus, the solution for this system is:
B = -1, C = -2