Respuesta :

Solving this system of equations, we have:

[tex]\begin{gathered} \begin{cases}2x+3y=6 \\ y=-\frac{2}{3}x+4\end{cases} \\ \text{Using the value of y from the 2nd equation in the 1st one:} \\ 2x+3(-\frac{2}{3}x+4)=6 \\ 2x-2x+12=6 \\ 12=6 \end{gathered}[/tex]

Since we got into a false statement, the system of equation has no solution.

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