Question

A circuit with a 21 V battery a 10 Ω resistor and 15 Ω resistor in series. What is the current throughout the circuit?

Answer 1

Given data:

* The voltage across the battery is,

$V=21\text{ volts}$

* The value of resistances given is,

$\begin{gathered} R_1=10\text{ ohm} \\ R_2=15\text{ ohm} \end{gathered}$

Solution:

The equivalent resistance of the given resistors connected in series is,

$\begin{gathered} R_{eq}=R_1+R_2 \\ R_{eq}=10+15 \\ R_{eq}=25\text{ ohm} \end{gathered}$

According to Ohm's law, the current through the circuit is,

$\begin{gathered} V=IR_{eq} \\ I=\frac{V}{R_{eq}} \\ I=\frac{21}{25} \\ I=0.84\text{ A} \end{gathered}$

Thus, the current through the circuit is 0.84 A.