How many atoms are contained in (6.73x10^2) grams of neon?

According to the Avogadro's constant
[tex]1mole\text{ of substance}=6.02\times10^{23}atoms[/tex]Given the following parameter
Mass of Neon = 6.73 * 10^2grams = 673grams
Determine the moles of Neon
[tex]\begin{gathered} mole\text{ of Neon}=\frac{mass}{molar\text{ mass}} \\ mole\text{ of Neon}=\frac{673}{20.18} \\ mole\text{ of Neon}=33.35moles \end{gathered}[/tex]Convert moles to atoms
[tex]\begin{gathered} atom\text{ of Neon}=33.35\times6.02\times10^{23}atoms \\ atom\text{ of Neon}=200.77\times10^{23}atoms \\ atom\text{ of Neon}=2.01\times10^{25}atoms \end{gathered}[/tex]