Question

C(t) = 2(t − 4)(t + 1)(t − 9)(t, C(t)) = (smallest t-value)(t, C(t)) = (t, C(t)) = (largest t-value)

Answer 1

Explanation

Given the function

$C(t)=2(t-4)(t+1)(t-9)$

The t values becomes

$\begin{gathered} (t-4)=0\Rightarrow t=4 \\ (t+1)=0\Rightarrow t=-1 \\ (t-9)=0\Rightarrow t=9 \end{gathered}$

Answer:

$\begin{gathered} (-1,0) \\ (4,0) \\ (9,0) \end{gathered}$