Question

Triangle ABC has vertices A= (-1, 7), B = (1, 1) and C= (3, 8). Triangle A'B'C' is formed when Triangle ABC is translated right by 4 and up by 2. Which statement is true? Choose all that apply. O The angles of Triangle ABC and Triangle A'B'C' are the same. O Triangle A'B'C is located in Quadrant 1. The perimeter of Triangle ABC and Triangle A'B'C' are the same.

Answer 1

The coordinates of XYZ are given as follows;

$\begin{gathered} X(-1,7),Y(1,1),Z(3,8) \\ \text{When the triangle is translated by 4 units to the right then we add 4 to the x coordinates} \\ \text{Also when its translated up by 2 units we add 2 to the y coordinates} \\ \text{Hence we now have;} \\ X\text{'(-1+4, 7+2)} \\ X^{\prime}(3,9) \\ Y^{\prime}(1+4,1+2) \\ Y^{\prime}(5,3) \\ Z^{\prime}(3+4,8+2) \\ Z^{\prime}(7,10) \end{gathered}$

The correct answer therefore is option A

X' (3, 9)

Y' (5, 3)

Z' (7, 10)