Question

A woman takes her dog Rover for a walk on a leash. To get the little pooch moving forward, she pulls on the leash with a force of 20.0 N at an angle of 37 degrees above the horizontal. 'a) How much force is tending to pull the dog forward? 'b) How much force is tending to lift Rover off the ground?

Answer 1

Answer:

a) The force tending to pull the dog forward = 16.0 N

b) The force tending to lift Rover off the ground is 12.0 N

Explanation:

The force at which the leash was pushed, F = 20.0 N

Angle at which the leash was pushed to the horizontal, θ = 37°

a) The amount of force tending to move the dog forward is the horizontal component of the force

$\begin{gathered} F_x=F\cos \theta \\ F_x=20\cos 37 \\ F_x=20(0.799) \\ F_x=15.98N \\ F_x=16.0N\text{ (1 dp)} \end{gathered}$

Therefore, 16.0 N of force is tending to pull the dog forward

b) The amount of force tending to lift the rover off the ground is the vertical component of the force

$\begin{gathered} F_y=F\sin \theta \\ F_y=20\sin 37 \\ F_y=12.04N \\ F_y=12.0N(1dp) \end{gathered}$

Therefore, the force tending to lift Rover off the ground is 12.0 N