Constants for waterHvap40.65 kJ/mol-285.83 kJ/mol6.03 kJ/mol4.186 J/g°CAHAHfusionspecific heatmolar mass 18.02 gHow much energy is consumed by thawing 4.3 g ice?

INFORMATION:
Is given that
And we must find how much energy is consumed by thawing 4.3 g ice
STEP BY STEP EXPLANATION:
To find it, we need to multiply the mass of the ice by the Hfusion
[tex]4.3g\times6.03\frac{kJ}{mol}[/tex]Since we need the energy, the answer must be in kJ. So, we need to use the molar mass to obtain the answer in kJ
[tex]4.3g\times\frac{1mol}{18.02g}\times6.03\frac{kJ}{mol}[/tex]Finally, when we simplify the expression, the answer will be in kJ
ANSWER:
A. 4.3 g x 1 mol/18.02 g x 6.03 kJ/mol