First, we find the equation that represents the situation
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Let's replace the points (110,6.60) and (135,8.10) where,
[tex]\begin{gathered} x_1=110 \\ x_2=135 \\ y_1=6.60 \\ y_2=8.10 \end{gathered}[/tex][tex]m=\frac{8.10-6.60}{135-110}=\frac{1.5}{25}=0.06[/tex]Once we have the slope of the line, we use the point-slope formula to find the equation
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-6.60=0.06(x-110) \\ y=0.06x-6.6+6.6 \\ y=0.06x \end{gathered}[/tex]The equation that represents the problem is y = 0.06x.
Now, let's transform 25 feet and 15 yards into inches.
We know that 1 foot is equivalent to 12 inches, so
[tex]25ft\cdot\frac{12in}{1ft}=300in[/tex]We know that 1 yard is equivalent to 36 inches, so
[tex]15yd\cdot\frac{36in}{1yd}=540in[/tex]Then, we evaluate the equation for x = 300 and x = 540.
[tex]\begin{gathered} y=0.06x=0.06\cdot300=18 \\ y=0.06x=0.06\cdot540=32.4 \end{gathered}[/tex]