Respuesta :

Step 1: Problem

Find the area of the figure below.

Step 2: Concept

Divide the figure into a rectangle (A) and a trapezium (B).

Step 3: Method

[tex]\begin{gathered} \text{Area of a rectangle A = Length x Breadth} \\ \text{Length = 32m} \\ \text{Breadth = 20m} \\ \text{Area of a rectangle A = 32 }\times20=640m^2 \end{gathered}[/tex]

[tex]\begin{gathered} \text{Area of a trapezium B = }\frac{1}{2}\times(s\text{ um of length of the parallel sides) x height} \\ \\ =\text{ }\frac{1}{2}\text{ }\times\text{ ( 16 + 20) x 8} \\ =\text{ }\frac{1}{2}\text{ }\times\text{ 36 x 8} \\ =144m^2 \end{gathered}[/tex]

Area of the figure = Area of rectangle A + Area of trapezium B

= 640 + 144

= 784

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