The function is decreasing on the interval (-0, 0)and increasing on the interval (0, 0).The function is increasing on the interval (-0,0)and decreasing on the interval (0, ).The function is increasing on the interval (-00, 0).The function is decreasing on the interval(-0, 0).

The function is decreasing on the interval 0 0and increasing on the interval 0 0The function is increasing on the interval 00and decreasing on the interval 0 Th class=

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D; The function is decreasing in the interval;

[tex](-\infty,\infty)[/tex]

Here, we want to interpret the given rate of change of the function

From what we have, coming from negative infinity, we can see that there is a decrease in the rate of change of the function. As we move closer to zero, we can see a decrease in the range value of the function

Now, moving away from zero, we can see that there is a continuous decrease as we move towards positive infinity. We can therefore conclude that there is a continuous decrease from the point x = 0 towards the point x = positive infinity

So, the correct choice here is that the function is decreasing in the interval negative infinity to positive infinity

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