Find f. Use C for the constant of the first anti derivative and d for the constant of the second derivative

we have the second derivative of the function f(x)
[tex]f^{\doubleprime}(x)=2x+9e^x[/tex]step 1
Find out the first antiderivative of the given function
[tex]f^{\prime}(x)=\int 2x+9e^x=x^2+9e^x+C[/tex]step 2
Find out the second antiderivative
[tex]f(x)=\int x^2+9e^x+C=\frac{x^3}{3}+9e^x+Cx+D[/tex]therefore
[tex]f(x)=\frac{x^3}{3}+9e^x+Cx+D[/tex]