Respuesta :

we have the second derivative of the function f(x)

[tex]f^{\doubleprime}(x)=2x+9e^x[/tex]

step 1

Find out the first antiderivative of the given function

[tex]f^{\prime}(x)=\int 2x+9e^x=x^2+9e^x+C[/tex]

step 2

Find out the second antiderivative

[tex]f(x)=\int x^2+9e^x+C=\frac{x^3}{3}+9e^x+Cx+D[/tex]

therefore

[tex]f(x)=\frac{x^3}{3}+9e^x+Cx+D[/tex]

ACCESS MORE