ANSWER:
b. Yes, by determining the average speed while braking and doubling it.
STEP-BY-STEP EXPLANATION:
Option A is not correct because both speeds, the final and the initial, are not taken into account.
To determine the correct answer, the first thing to do is to do it mathematically. Just like this:
[tex]\begin{gathered} v=u+at\rightarrow a=\frac{v-u}{t} \\ \\ s=ut+\frac{1}{2}at^2 \end{gathered}[/tex]We replacing
[tex]\begin{gathered} s=ut+\frac{1}{2}(\frac{v-u}{t})t^2 \\ \\ s=ut+\frac{1}{2}vt-\frac{1}{2}ut \\ \\ s=\frac{1}{2}t(u+v) \\ \\ v=0 \\ \\ s=\frac{1}{2}tu\rightarrow u=\frac{2s}{t} \end{gathered}[/tex]The average speed, that is, the average between the initial speed and the final speed, is determined since the final speed is 0, because it ends up braking. We can calculate the initial start since we know the total braking time (4 seconds) and the total distance we also know to be 20 meters, using the previous equations.
Therefore, the correct answer is: b. Yes, by determining the average speed while braking and doubling it.